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315 f g h ` _ k l \ h l j m ^ h \ _ i h t e Z j k d Z b k l h j b y g Z g _ f k d b b t e Z j k d b _ a b d K i h j _ ^ ^ h k l h \ _ j g b ^ Z g g b _ i h qDeflnition Given a function f(t), t ‚ 0, its Laplace transform F(s) = Lff(t)g is deflned as F(s) = Lff(t)g = Z 1 0 e¡stf(t)dt = lim A!1 Z A 0 e¡stf(t)dt We say the transform converges if the limit exists, and diverges if not Next we will give examples on computing the Laplace transform of given functions by deflnition Example 1 fThe fbi e g d a b m c v y h x j z s y z q o g e c i t s u j e x e m s e c u r i t y a a x d c t e y r e b b o r k n a b g r a d p i s t o l u c c e e a i t a
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Know answer of objective question Y, B, T, G, O, ?F(x y)g(y)dy is well de ned for ae x That is, f(x y)g(y) is integrable on Rd for ae x Proof Let h(x;y) = f(x y)g(y) By part (b), his integrable on Rd Then by part (i) of Fubini's Theorem (Theorem 31), the slice hx(y) = f(x y)g(y) is integrable with respect to yfor ae x Proposition 011 (Exercise 21d) Let f;gbe integrable on RdK is onto, because g e Y but g (x) for any x in X Kis onto, because there is exactly one element of X sent by K to the same element of Y Kis onto, because no two elements of X are sent by k to the same element of Y Kis not onto, because g e Y but g K(x) for any x in X K is not onto, because no two elements of X are sent by k to the same
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